Kotlin Program to Find the Largest Among Three Numbers
In this program, you’ll learn to find the largest among three numbers using if else and when statement in Kotlin.
Example 1: Find Largest Among three numbers using if..else statement
fun main(args: Array<String>) {
val n1 = -4.5
val n2 = 3.9
val n3 = 2.5
if (n1 >= n2 && n1 >= n3)
println("$n1 is the largest number.")
else if (n2 >= n1 && n2 >= n3)
println("$n2 is the largest number.")
else
println("$n3 is the largest number.")
}
When you run the program, the output will be:
3.9 is the largest number.
In the above program, three numbers -4.5
, 3.9
and 2.5
are stored in variables n1, n2 and n3 respectively.
Then, to find the largest, the following conditions are checked using if else statements
- If n1 is greater or equals to both n2 and n3, n1 is the greatest.
- If n2 is greater or equals to both n1 and n3, n2 is the greatest.
- Else, n3 is the greatest.
The greatest number can also be found using a when
statement.
Example 2: Find the largest number among three using when statement
fun main(args: Array<String>) {
val n1 = -4.5
val n2 = 3.9
val n3 = 5.5
when {
n1 >= n2 && n1 >= n3 -> println("$n1 is the largest number.")
n2 >= n1 && n2 >= n3 -> println("$n2 is the largest number.")
else -> println("$n3 is the largest number.")
}
}
When you run the program, the output will be:
5.5 is the largest number.
In the above program, instead of using an if..else if..else
block, we use when
statement.
So, the above conditions in both the programs are the same.