String copy in C
C program to copy a string using library function strcpy and without using strcpy.
String copy C program
#include <stdio.h>
#include <string.h>
int main()
{
char source[1000], destination[1000];
printf(“Input a string\n“);
gets(source);
strcpy(destination, source);
printf(“Source string: %s\n“, source);
printf(“Destination string: %s\n“, destination);
return 0;
}
Output of program:
Copy string in C without using strcpy
#include <stdio.h>
int main()
{
int c = 0;
char s[1000], d[1000] = “What can I say about my programming skills?”;
printf(“Before copying, the string: %s\n“, d);
printf(“Input a string to copy\n“);
gets(s);
while (s[c] != ‘\0‘) {
d[c] = s[c];
c++;
}
d[c] = ‘\0‘;
printf(“After copying, the string: %s\n“, d);
return 0;
}
Output of the program:
Input a string to copy
My programming skills are improving.
After copying, the string: My programming skills are improving.
Creating a function to copy a string
#include <stdio.h>
void copy_string(char [], char []);
int main() {
char s[1000], d[1000];
printf(“Input a string\n“);
gets(s);
copy_string(d, s);
printf(“The string: %s\n“, d);
return 0;
}
void copy_string(char d[], char s[]) {
int c = 0;
while (s[c] != ‘\0‘) {
d[c] = s[c];
c++;
}
d[c] = ‘\0‘;
}
C program to copy a string using pointers
Function to copy a string using pointers.
while (*source) {
*target = *source;
source++;
target++;
}
*target = ‘\0‘;
}