#include <stdio.h>
int main()
{
int data[5], i;
printf("Enter elements: ");
for(i = 0; i < 5; ++i)
scanf("%d", data + i);
printf("You entered: \n");
for(i = 0; i < 5; ++i)
printf("%d\n", *(data + i));
return 0;
}

Output

Enter elements: 1
2
3
5
4
You entered: 
1
2
3
5
4

In this program, the elements are stored in the integer array data.

Then, using the for loop, each element in the data is traversed and printed using the pointer method.

a step-by-step explanation of a C program that accesses array elements using a pointer:

#include <stdio.h>

int main() {
    int arr[5] = {10, 20, 30, 40, 50}; // declare and initialize an integer array

    int *ptr = arr; // declare and initialize an integer pointer to point to the first element of the array

    for (int i = 0; i < 5; i++) {
        printf("Value of arr[%d] = %d\n", i, *(ptr + i)); // access each element using pointer arithmetic
    }

    return 0;
}

Let’s break it down step-by-step:

1. We include the necessary header file stdio.h for input/output functions.

2. We declare an integer array arr of size 5 and initialize it with some values.

3. We declare an integer pointer ptr and initialize it to point to the first element of the array arr using ptr = arr.

4. We use a for loop to iterate over all the elements of the array arr.

5. Inside the loop, we use pointer arithmetic to access each element of the array. We use the expression *(ptr + i) to access the element at the index i of the array arr.

6. We print the value of each element of the array using printf().

7. Finally, we return 0 to indicate successful completion of the program.