C program to add two numbers using pointers
C program for the addition of two numbers using pointers. In the program, we have two integer variables x and y and two pointer variables p and q. We assign the addresses of x and y to p and q respectively and then assign the sum of x and y to the variable sum. Remember ‘&’ is the address of operator and ‘*’ is value at the address operator.
C programming code
#include <stdio.h>
int main()
{
int first, second, *p, *q, sum;
printf(“Enter two integers to add\n“);
scanf(“%d%d”, &first, &second);
p = &first;
q = &second;
sum = *p + *q;
printf(“Sum of the numbers = %d\n“, sum);
return 0;
}
Output of program:
C program to add numbers using call by reference
#include <stdio.h>
long add(long *, long *);
int main()
{
long first, second, *p, *q, sum;
printf(“Input two integers to add\n“);
scanf(“%ld%ld”, &first, &second);
sum = add(&first, &second);
printf(“(%ld) + (%ld) = (%ld)\n“, first, second, sum);
return 0;
}
long add(long *x, long *y) {
long sum;
sum = *x + *y;
return sum;
}