# Python program that finds all Armstrong numbers in a given range:

## Python program that finds all Armstrong numbers in a given range:

``````start = int(input("Enter the start of the range: "))
end = int(input("Enter the end of the range: "))

print("Armstrong numbers between", start, "and", end, "are:")

for number in range(start, end + 1):
# Initialize variables
original_number = number
result = 0

# Find the number of digits in the number
number_of_digits = len(str(number))

# Check if the number is Armstrong
while number > 0:
digit = number % 10
result += digit ** number_of_digits
number //= 10

if original_number == result:
print(original_number)
``````

The program prompts the user to enter the start and end of the range using the input() function, and stores the values in the variables “start” and “end”. It then uses a for loop to iterate through the range of numbers between start and end (inclusive). For each number in the range, it uses the same logic as the previous example to check if the number is an Armstrong number, if yes, it prints the number.

You can also use the built-in python function `pow()` to raise the digit to the power of the number of digits and list comprehension to generate the list of digits in the number,

``````start = int(input("Enter the start of the range: "))
end = int(input("Enter the end of the range
``````