Java Program to Check Whether an Alphabet is Vowel or Consonant

In this program, you’ll learn to check whether an alphabet is a vowel or a consotant using if..else and switch statement in Java.

Example 1: Check whether an alphabet is vowel or consonant using if..else statement

  1. public class VowelConsonant {
  2. public static void main(String[] args) {
  3. char ch = 'i';
  4. if(ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u' )
  5. System.out.println(ch + " is vowel");
  6. else
  7. System.out.println(ch + " is consonant");
  8. }
  9. }

When you run the program, the output will be:

i is vowel

In the above program, 'i' is stored in a char variable ch. In Java, you use double quotes (" ") for strings and single quotes (' ') for characters.

Now, to check whether ch is vowel or not, we check if ch is any of: ('a', 'e', 'i', 'o', 'u'). This is done using a simple if..else statement.

We can also check for vowel or consonant using a switch statement in Java.


Example 2: Check whether an alphabet is vowel or consonant using switch statement

  1. public class VowelConsonant {
  2. public static void main(String[] args) {
  3. char ch = 'z';
  4. switch (ch) {
  5. case 'a':
  6. case 'e':
  7. case 'i':
  8. case 'o':
  9. case 'u':
  10. System.out.println(ch + " is vowel");
  11. break;
  12. default:
  13. System.out.println(ch + " is consonant");
  14. }
  15. }
  16. }

When you run the program, the output will be:

z is consonant

In the above program, instead of using a long if condition, we replace it with a switch case statement.

If ch is either of cases: ('a', 'e', 'i', 'o', 'u'), vowel is printed. Else, default case is executed and consonant is printed on the screen.