Example 1: Find Largest Among three numbers using if..else statement

1. public class Largest {
3. public static void main(String[] args) {
5. double n1 = -4.5, n2 = 3.9, n3 = 2.5;
7. if( n1 >= n2 && n1 >= n3)
8. System.out.println(n1 + " is the largest number.");
10. else if (n2 >= n1 && n2 >= n3)
11. System.out.println(n2 + " is the largest number.");
13. else
14. System.out.println(n3 + " is the largest number.");
15. }
16. }

When you run the program, the output will be:

3.9 is the largest number.

In the above program, three numbers -4.5, 3.9 and 2.5 are stored in variables n1, n2 and n3 respectively.

Then, to find the largest, the following conditions are checked using if else statements

• If n1 is greater or equals to both n2 and n3, n1 is the greatest.
• If n2 is greater or equals to both n1 and n3, n2 is the greatest.
• Else, n3 is the greatest.

The greatest number can also be found using a nested if..else statement.

Example 2: Find the largest number among three using nested if..else statement

1. public class Largest {
3. public static void main(String[] args) {
5. double n1 = -4.5, n2 = 3.9, n3 = 5.5;
7. if(n1 >= n2) {
8. if(n1 >= n3)
9. System.out.println(n1 + " is the largest number.");
10. else
11. System.out.println(n3 + " is the largest number.");
12. } else {
13. if(n2 >= n3)
14. System.out.println(n2 + " is the largest number.");
15. else
16. System.out.println(n3 + " is the largest number.");
17. }
18. }
19. }

When you run the program, the output will be:

5.5 is the largest number.

In the above program, instead of checking for two conditions in a single if statement, we use nested if to find the greatest.

Then, to find the largest, the following conditions are checked using if else statements

• If n1 is greater or equals to n2,
  • and if n1 is greater or equals to n3, n1 is the greatest.
  • else, n3 is the greatest.
• Else,
  • if n2 is greater or equals to both n3, n2 is the greatest.
  • else, n3 is the greatest.